Force Vs. Mass Graph

Force Vs. Mass

Data Analysis:
 VM:As the mass increases, the force increases linearly.
MM:Force=(9.8985Newtons/Kg)Mass - 0.0171 Newtons
Slope: For every 9.8985 Newtons, the mass increases 1 Kg
Y-Int: When the mass is 0 Kg, the Newtons is -0.0171 the force is -0.0171 N - and is it really?  Does that make sense?

 Claims/Evidence: 
Mass is different than weight because mass is the amount of matter the thing has, mass will not change wherever you are,  in space, on the moon, etc, but the weight changes because it is how much gravity is pulling, and gravity is different on other planets and in space than the Earth's gravity. Gravity is also the same around the world and no place has more gravity than other places. There is also the same force of gravity for everything regardless of mass.No  - force of gravity is dependent on mass - see graph.  The field strength is the same We tested this out in class when we dropped the ball and the textbook and they fell at the same time and hit the table at the same time. There is also air resistance, but the gravity is still the same.the force/mass ratio is the same

Conclusion:
 I conclude that gravity has the same force all over the world. When i compared graphs with my peers who also performed the same experiment, we all  had very similar graphs. This happened because the force of gravity is the same on all parts of Earth. We found the equation Fg=MG. Fg is the force of gravity(weight), M is the mass, and G is the gravitational field strength force. This equation could work to find any
 weight by plugging the necessary elements in.
yes but just be careful on wording - force of gravity is weight, and of course everything does not weigh the same...
Data Collection:

Mass(kg)	Force(N)
0.06	0.5865
0.07	0.6765
0.1	0.9665
0.15	1.463
0.25	2.456
0.55	5.429

Dueling Buggies Lab

Dueling Buggies Lab

Objective Statement: We are looking for when a fast buggy and slow buggy intersect at a certain distance at 180cm. One buggy will start at 180cm and go in a negative direction at a fast pace and one buggy will start at 0cm and go in a positive direction at a slow pace.

Procedure: We will first, measure the speeds of the buggies using our phone as timers and a meter stick to measure distance. After we get the speeds of the buggies, we will then place the fast buggy at 180 cm and the slow buggy at 0 cm. We will then start the buggies at the same time and see if they intersect each other at the same place it says graphically.

Data Analysis:

Slow Buggy (100cm)	Fast Buggy (100cm)
5.97sec	2.74sec
6.36sec	2.49sec
6.47sec	2.44sec
Average: 6.27sec	Average: 2.56sec
100cm/6.27sec=15.95cm/sec	100cm/2.56sec=39.06cm/sec

Now that we figured the speeds of the buggies, we found out graphically where the two buggies would meet if we placed the fast one at 180cm and the slow one at 0cm. We made the fast buggy's slope negative because it is going in a negative direction and made the Y-intercept 180 because the starting point is 180cm. good!

After we graphed the equations, we found out that the buggies would intersect at 52.191cm because that is the Y-value where the lines on the graph intersect.excellent!

After we tested graphically, we tested with the actual buggies. The buggies met at a very close point to 52.191cm.

Conclusion:

I conclude that the buggies met at a close enough point to where it was the same as the graph. We may have had problems like reaction time and the straightness of the buggies, but in general the buggies met maybe only 1 or 2 cm from exactly 52.191cm. The lab was very successful.great job!